stuff from before

party.ts

@@ -0,0 +1,84 @@
+// Making a whole new file for this, that's how complex it looks like it'll be.
+import { Canvas, createCanvas, loadImage, GlobalFonts, SKRSContext2D } from "@napi-rs/canvas";
+
+import {
+  GenerateBattlerOptions,
+  GenerateBattleImageOptions,
+  PlayerActionOptions,
+  Colour,
+  Opponents,
+  PlayerActions,
+  CustomActionOptions
+} from "./types";
+
+import {
+  generateBattler, drawText, applyText,
+} from "./utils";
+
+type Rank = "Beginner" | "Casual" | "Pro" | "Master";
+
+type PartyOptions = {
+  ready: string;
+  
+  player1: string;
+  username1: string;
+  rank1: Rank;
+
+  player2?: string;
+  username2?: string;
+  rank2?: Rank;
+
+  player3?: string;
+  username3?: string;
+  rank3?: Rank;
+
+  player4?: string;
+  username4?: string;
+  rank4?: Rank;
+
+  player5?: string;
+  username5?: string;
+  rank5?: Rank;
+
+  player6?: string;
+  username6?: string;
+  rank6?: Rank;
+
+  player7?: string;
+  username7?: string;
+  rank7?: Rank;
+
+  player8?: string;
+  username8?: string;
+  rank8?: Rank;
+}
+
+function generateMatchType(opts: PartyOptions): string {
+  const keys: (keyof PartyOptions)[] = [
+    'player1', 'player2', 'player3', 'player4', 'player5', 'player6', 'player7', 'player8'
+  ];
+  let playerCount = keys.reduce((count, key) => opts[key] ? count + 1 : count, 0);
+  // If there's an odd number of players, round up to the next even number
+  if (playerCount % 2 !== 0) {
+    playerCount++;
+  }
+  // Divide by 2 to get the number for each team, since it's evenly matched (e.g. "1v1", "2v2")
+  const teamSize = playerCount / 2;
+  return `${teamSize}v${teamSize}`;
+}
+
+
+export default async function party(request: Request, url: import("url").URL): Promise<Response> {
+  const opts = Object.fromEntries(
+    Array.from(url.searchParams.entries())
+      .map(([key, value]) => [key, value.replaceAll('+', ' ')]),
+  ) as PartyOptions;
+
+  if (!opts.player1 && !opts.username1 && !opts.rank1) {
+    return Response.json({
+      error: "At least one player must be in the party"
+    })
+  }
+
+
+}